快速业务通道

MD5应用的一点理解及Linux实现源码

作者 佚名技术 来源 Linux系统 浏览 发布时间 2012-04-05
xt *ctx) { ctx->buf[0] = 0x67452301; ctx->buf[1] = 0xefcdab89; ctx->buf[2] = 0x98badcfe; ctx->buf[3] = 0x10325476; ctx->bits[0] = 0; ctx->bits[1] = 0; } /* * Update context to reflect the concatenation of another buffer full * of bytes. */ void MD5Update(struct MD5Context *ctx, unsigned char const *buf, unsigned len) { uint32 t; /* Update bitcount */ t = ctx->bits[0]; if ((ctx->bits[0] = t ((uint32) len << 3)) < t) ctx->bits[1] ; /* Carry from low to high */ ctx->bits[1] = len >> 29; t = (t >> 3) & 0x3f; /* Bytes already in shsInfo->data */ /* Handle any leading odd-sized chunks */ if (t) { unsigned char *p = (unsigned char *) ctx->in t; t = 64 - t; if (len < t) { memcpy(p, buf, len); return; } memcpy(p, buf, t); byteReverse(ctx->in, 16); MD5Transform(ctx->buf, (uint32 *) ctx->in); buf = t; len -= t; } /* Process data in 64-byte chunks */ while (len >= 64) { memcpy(ctx->in, buf, 64); byteReverse(ctx->in, 16); MD5Transform(ctx->buf, (uint32 *) ctx->in); buf = 64; len -= 64; } /* Handle any remaining bytes of data. */ memcpy(ctx->in, buf, len); } /* * Final wrapup - pad to 64-byte boundary with the bit pattern * 1 0* (64-bit count of bits processed, MSB-first) */ void MD5Final(unsigned char digest[16], struct MD5Context *ctx) { unsigned count; unsigned char *p; /* Compute number of bytes mod 64 */ count = (ctx->bits[0] >> 3) & 0x3F; /* Set the first char of padding to 0x80. This is safe since there is always at least one byte free */ p = ctx->in count; *p = 0x80; /* Bytes of padding needed to make 64 bytes */ count = 64 - 1 - count; /* Pad out to 56 mod 64 */ if (count < 8) { /* Two lots of padding: Pad the first block to 64 bytes */ memset(p, 0, count); byteReverse(ctx->in, 16); MD5Transform(ctx->buf, (uint32 *) ctx->in); /* Now fill the next block with 56 bytes */ memset(ctx->in, 0, 56); } else { /* Pad block to 56 bytes */ memset(p, 0, count - 8); } byteReverse(ctx->in, 14); /* Append length in bits and transform */ ((uint32 *) ctx->in)[14] = ctx->bits[0]; ((uint32 *) ctx->in)[15] = ctx->bits[1]; MD5Transform(ctx->buf, (uint32 *) ctx->in); byteReverse((unsigned char *) ctx->buf, 4); memcpy(digest, ctx->buf, 16); memset(ctx, 0, sizeof(ctx)); /* In case it''s sensitive */ } #ifndef ASM_MD5 /* The four core functions - F1 is optimized somewhat */ /* #define F1(x, y, z) (x & y | ~x & z) */ #define F1(x, y, z) (z ^ (x & (y ^ z))) #define F2(x, y, z) F1(z, x, y) #define F3(x, y, z) (x ^ y ^ z) #define F4(x, y, z) (y ^ (x | ~z)) /* This is

凌众科技专业提供服务器租用、服务器托管、企业邮局、虚拟主机等服务,公司网站:http://www.lingzhong.cn 为了给广大客户了解更多的技术信息,本技术文章收集来源于网络,凌众科技尊重文章作者的版权,如果有涉及你的版权有必要删除你的文章,请和我们联系。以上信息与文章正文是不可分割的一部分,如果您要转载本文章,请保留以上信息,谢谢!

分享到: 更多

Copyright ©1999-2011 厦门凌众科技有限公司 厦门优通互联科技开发有限公司 All rights reserved

地址(ADD):厦门软件园二期望海路63号701E(东南融通旁) 邮编(ZIP):361008

电话:0592-5908028 传真:0592-5908039 咨询信箱:web@lingzhong.cn 咨询OICQ:173723134

《中华人民共和国增值电信业务经营许可证》闽B2-20100024  ICP备案:闽ICP备05037997号